Question

Find the sum of the first 6 terms of the following series, to the nearest integer.

16, 32, 64,...

Answer 1

1008

Explanation:

geometric sequence:

a=16

r=32/16=2

Sum of GS:

s=a(1-r^n)/(1-r)

S(6)=16(1-2^6)/(1-2)

=1008