Question

Can anyone help me with this algebraic expression

(4a+3b)² (3a-4b)²​

Answer 1

`(4a + 3b)(4a + 3b)(3a - 4b)(3a - 4b) \\ {16a}^(2) + 12ab + {9b}^(2) + 12ab + {9a}^(2) + 12ab + 12ab + {16b}^(2) \\ {16a}^(2) + {9a}^(2) + {9b}^(2) + {16b}^(2) + 12ab + 12ab + 12ab + 12ab \\ {25a}^(2) + {25b}^(2) + 48ab`

Answer 2

=144a⁴−168a³b−239a²b²+168ab³+144b⁴

Step-by-step explanation:

=144a⁴−168a³b−239a²b²+168ab³+144b⁴