Question

Pls help! Solve the equation by using quadratic formula.

-2x’2 + 4x = 5

Answer 1

`x=(2\pm i√(6))/(2)`

Explanation:

`-2x^2+4x=5\\\\-2x^2+4x-5=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\ \\x=(-4\pm√((4)^2-4(-2)(-5)))/(2(-2))\\\\x=(-4\pm√(16-40))/(-4)\\\\x=(-4\pm√(-24))/(-4)\\ \\x=(-4\pm2i√(6))/(-4)\\ \\x=(2\pm i√(6))/(2)`