Question

Equation of the line that passes through points (-4,8) and (1,3)

Answer 1

y=-x+4

Explanation:

m=(y2-y1)/(x2-x1)

m=(3-8)/(1-(-4))

m=-5/(1+4)

m=-5/5

m=-1

y-y1=m(x-x1)

y-8=-1(x-(-4))

y-8=-(x+4)

y-8=-x-4

y=-x-4+8

y=-x+4