Question

If 0.647 mil of oxygen are used in the burning of propane, how many moles of CO2 are produced

Answer 1

1.733 x 10⁻⁴ mole CO₂(g)

Step-by-step explanation:

Assuming the rxn given is at STP conditions ...

C₃H₈ + 5O₂ => 3CO₂ + 4H₂O

Given: Excess = 0.647ml ?(moles) -----

= 0.000647Liters

= 6.47 X 10⁻⁴L/22.4L·mol⁻¹

= 1.733 x 10⁻⁵ mol O₂

moles CO₂ = 3/5(2.89 x 10⁻⁴)mole CO₂ = 1.733 x 10⁻⁵ mole CO₂