asked 113k views
2 votes
What is the value of p(x)=6x^4+2x^3-x+2 at x=0

asked
User Berko
by
8.7k points

2 Answers

6 votes

Answer:

2

Explanation:

6×0^4+2×0^3-0+2

=0+0-0+2

=2

answered
User Blacktrance
by
8.2k points
10 votes

Answer:

2

Explanation:

Plug in x=0

p(x)=6x^4+2x^3-x+2 at x=0

p(0)=6(0)^4+2(0)^3-(0)+2

p(0)=2

answered
User Bitpshr
by
8.6k points

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