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In ΔABC, the measure of ∠C=90°, the measure of ∠B=15°, and BC = 2.8 feet. Find the length of CA to the nearest tenth of a foot.

In ΔABC, the measure of ∠C=90°, the measure of ∠B=15°, and BC = 2.8 feet. Find the length of CA to the nearest tenth of a foot.
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In ΔABC, the measure of ∠C=90°, the measure of ∠B=15°, and BC = 2.8 feet. Find the length of CA to the nearest tenth of a foot.

asked
User MSohm
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8.0k points

1 Answer

13 votes

Answer:0.8 feet

Step-by-step explanation:got it right

answered
User Elliot Nelson
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