Question

Solve algebraically the simultaneous equations

x^2 – 4y^2 = 5
3x + 4y = 13
Please correctly pair your answers and write them on separate lines.

Answer 1

Step-by-step explanation:

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Answer 2

To solve the simultaneous equations x^2 – 4y^2 = 5 and 3x + 4y = 13 algebraically, we can use the method of substitution or elimination. The solutions are pairs of values for x and y. You can write them on separate lines.

Step-by-step explanation:

To solve the simultaneous equations x^2 – 4y^2 = 5 and 3x + 4y = 13 algebraically, we can use the method of substitution or elimination. Let's solve using elimination:

1. Multiply the second equation by 4 to make the coefficients of y the same in both equations. This gives us 12x + 16y = 52.
2. Now subtract the first equation from the second equation to eliminate y. This gives us 12x + 16y - (x^2 – 4y^2) = 52 - 5.
3. Simplifying the equation, we have x^2 - 12x + 20y^2 = -47.
4. Next, we can rearrange the equation to isolate x: x^2 - 12x + 20y^2 + 47 = 0.
5. This quadratic equation can be solved using the Quadratic Formula or factoring, to find the values of x.
6. Once we have the values of x, we can substitute them back into the second equation to solve for y.

Therefore, the solutions are pairs of values for x and y. You can write them on separate lines.

Learn more about Solving Simultaneous Equations