Question

a bag contains 4 blue and 6 green marbles. two marbles are selected at a random from the bag. if the first marble is not replaced before the second marble is drawn

Answer 1

4 ÷ 10

Explanation:

The computation of P is shown below:

If we add two marbles i.e.

= 4 + 6

= 10 marbles

Now if we draw the second marble

P(blue) = Blue marbles ÷ total marbles

= 4 ÷ 10

In the other case

P( blue second given a green first) = 4 ÷ 10