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How many moles are in 124.7 g of Ba(OH)2

1 Answer

9 votes

Answer:

0.73 mol

Step-by-step explanation:

No. of moles(n)= Given mass/molar mass.

Given mass=124.7g

Molar mass of Ba(OH)2= Molar mass of (Barium+2Oxygen+2Hydrogen)=137+32+2=171g

No. of moles= 124.7g/171g=0.73 mol

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User EmmyS
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