Answer:
no real solutions
Explanation:
the given quadratic equation is 3x²-x+5=0
in the equation:
a=3
b=-1 (in front of the x)
c=5
the quadratic formula is (-b±√(b²-4ac))/2a
substitute the numbers into the formula
(1±√(1-4(3*5))/6
solve the expression under the square root:
√(1-4(3*5))
√(1-4(15))
√(1-60)
√-59
you cannot find the square root of a negative number, so the answer is no real solutions
Hope this helps!