Question

9 A rectangle of perimeter 42 cm is

pcm long and q cm broad. If the
difference between the length and
breadth is 9 cm. find
pand q
the area of the rectangle
​

Answer 1

The correct answer is = p = 15 and q = 6.

Explanation:

Given:

Perimeter of rectangle = 42 cm

p - q = 9 cm

length = p

width = q

we know:

Perimeter of rectangle= 2(l+w)

solution:

42 = 2(P+q)

21= p+q

Difference of p and q = 9 cm.

Then, P+q=21 .... 1

P-q=9 ....2

Adding both 1 and 2

2P = 30

P= 15cm and

q = 15-9

= 6cm