2x^2+3x-7=0 2x^(2) + 3x - 7 = 0 ​

Question

2x^2+3x-7=0

`2x^(2) + 3x - 7 = 0`
​

Answer 1

x =
`(-3\pm√(65) )/(4)`

It is written like this in latex code: $\frac{-3\pm\sqrt{65}}{4}$

Explanation: