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Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof is not correct. What is the first mistake in Ismail's proof?

Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof is not correct. What is the first mistake in Ismail's proof?
asked 192k views
7 votes
Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof is not correct.

What is the first mistake in Ismail's proof?

Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof-example-1
Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof-example-1
Ismail tried to prove that sin(θ) = cos(90°− θ) using the following diagram. His proof-example-2
asked
User Nab
by
8.3k points

2 Answers

12 votes

Answer:

c

Explanation:

answered
User MuffinTheMan
by
8.3k points
3 votes

Answer:

  • C. Ismail used the wrong sides in his ratio for cos (90 - θ)

Explanation:

All steps correct apart from:

  • cos (90° - θ) = AC/BC

It should be

  • cos (90° - θ) = AB/BC

Correct choice is C

answered
User Segundo
by
7.7k points
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