Question

A square pyramid has side lengths of 4 and the height of 6 what is the surface area, rounded to the nearest tenth?

Answer 1

66.59

Explanation:

The surface area can be calculated as follows

= a^2 + 2a √ a^2/4 + h^2

= 4^2 + 2(4) √ 4^2/4 + 6^2

= 16 + 8 √16/4 + 36

= 24 √ 4+36

= 24 √40

= 66.59