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The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y-1 = (x - 12). What is the standard form of the equation for this line?

The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y-1 = (x - 12). What is the standard form of the equation for this line?
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The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y-1 = (x - 12). What is

the standard form of the equation for this line?

asked
User RoccoB
by
7.8k points

1 Answer

10 votes

Answer:

-y+(x-12)=-1

Explanation:

answered
User AgentRegEdit
by
7.2k points
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