Question

what would the ph be at the end of an enzyme-catalyzed reaction if it were carried out in a 0.1 m phosphate buffer of pka 6.86 and 0.005 m of acid was produced during the reaction

Answer 1

Ph of the enzyme -catalyzed reaction = 6.77

Step-by-step explanation:

Given data:

concentration phosphate buffer = 0.1 m

pka. = 6.86

concentration of acid in the reaction = 0.005 m

Determine the Ph at the end of the reaction

For a balanced buffer solution ; Acid amount = base amount

first we will determine the concentration of acid and base in relation to the buffer

acid = 0.1 / 2 = 0.05

base = 0.1 /2 = 0.05

The chemical reaction of the buffer can be expressed as attached below

PH = pka + log
`((0.045)/(0.055) )` =

= 6.86 + log ( 0.8181 ) = 6.77