Question

Find the equation of the line through point (−3,8) and perpendicular to y=27x+117.

Answer 1

y - 8 = (-1/27)(x + 3)

Explanation:

the slope of a line perpendicular to the given y = 27x + 117 is the negative reciprocal of 27, that is, -1/27. Using the point-slope form y - k =m(x - h) to write the new equation, we get:

y - 8 = (-1/27)(x + 3)