Question

Find, to the nearest foot, the length of the diagonal of a square whose side is 8 feet.

Answer 1

a^2 + b^2 = c^2
8^2 + 8^2 = c^2
64 + 64 = c^2
128 = c^2
squareroot 128 = c
11.3.... = c
so to the nearest foot the length of the diagonal is 11 feet