Question

-6a2 – 18a + 240
AC Method

Answer 1

`- 6( {a}^(2) + 3a - 34)`

Step By Step Explanations:

1) FACTOR OUT THE COMMON TERM 6.

`- 6( {a}^(2 ) + 3a - 34)`

therefor the answer is, -6(a² + 3a - 34 )