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What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other

What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other
asked 48.2k views
13 votes
What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other

asked
User Dangling Cruze
by
8.7k points

1 Answer

12 votes

Answer:

86% - 14% = 72%

Step-by-step explanation:

answered
User Nigel Benns
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8.8k points
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