Question

2. How many grams of methane must be burned to produce 2.05 grams of water in the complete combustion reaction?

The unbalanced equation for the reaction is: _CH418) + _ 0218) ►_CO2(8) +_ H2O(8)

Answer 1

0.88 g

Step-by-step explanation:

The balanced reaction equation is;

CH4(g) + 2O2(g) ----------> CO2(g) + 2H2O(l)

Number of moles in 2.05g of water = 2.05g/18g/mol = 0.11 moles

If 1 mole of CH4 yields 2 moles of water

x moles of CH4 yields 0.11 moles of water

2x = 0.11

x = 0.11/2

x= 0.055 moles

Molar mass of methane = 16 g/mol

Mass of methane = 16 g/mol * 0.055 moles

Mass of methane =0.88 g