Question

Find the 12th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, 5.

Answer 1

Solution,
Common differences(d)= 9
First term (a)= 5
Now
12th term( t12)= a+(n-1)d
=5+(12-1)9 Therfore, tn= t12
=5+11*9
=5+99
=104 is the answer