Question

15. Factor 54m² + 12m³.

Answer 1

`{6\left( 2m^(3)+9m^(2)\right) }\)`

Explanation:

First: Rearrange Terms

`\(54m^(2)+12m^(3)\)\\12m^(3)+54m^(2)\)`

Next: Common Factor

`{12m^(3)+54m^(2)}\)\\{6\left( 2m^(3)+9m^(2)\right) }\)`

Last: Find one factor

`{6\left( 2m^(3)+9m^(2)\right) }\)`

Hence, the final answer is
`{6\left( 2m^(3)+9m^(2)\right) }\)`