Question

An object is dropped from the top of a 400-ft building. The height h of the ball after t seconds is modeled by the equation h=16f^2+400. How long is the ball in the air?

Answer 1

To find how long the ball is in the air, we need to find the time it takes for the height of the ball to reach 0.

Given the equation h = 16t^2 + 400, we set h = 0 and solve for t:

0 = 16t^2 + 400

Dividing both sides of the equation by 16:

0 = t^2 + 25

Rearranging the equation:

t^2 = -25

Since time cannot be negative, there are no real solutions for t in this case.

Therefore, the ball is not in the air for any amount of time.