Answer:
a₁ = 707 a₂ = 713
Explanation:
the nth term of an arithmetic sequence is
= a₁ + (n - 1)d
a₁ is the first term, d the common difference , n the term number
given
a₅₀ = 1001 , then
a₁ + 49d = 1001 ← substitute d = 6
a₁ + 49(6) = 1001
a₁ + 294 = 1001 ( subtract 294 from both sides )
a₁ = 707
and a₂ = a₁ + d = 707 + 6 = 713