Final answer:
The final velocity of the jet at takeoff is 77.5 m/s.
Step-by-step explanation:
To find the final velocity (v) of the jet at takeoff, we can use the equation of motion: v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. In this case, the jet starts from rest, so u = 0. The distance traveled (s) is given as 93 m and the time (t) is given as 1.2 s. We can rearrange the equation to solve for v: v = s/t. Plugging in the values, we get v = 93 m / 1.2 s = 77.5 m/s.
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