Answer:
3925
Explanation:
The first 50 terms of the sequence are:
5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65, 68, 71, 74, 77, 80, 83, 86, 89, 92, 95, 98, 101, 104, 107, 110, 113, 116, 119, 122, 125, 128, 131, 134, 137, 140, 143, 146, 149, 152.
To find the sum of the first 50 terms, we can use the formula for the sum of an arithmetic series:
S = (n/2)(a1 + an)
where S is the sum of the series, n is the number of terms (in this case n=50), a1 is the first term (in this case a1=5), and an is the nth term (in this case a50=152).
Plugging in the values, we get:
S = (50/2)(5 + 152)
S = 25(157)
S = 3925
Therefore, the sum of the first 50 terms of the sequence is 3925.