asked 198k views
2 votes
in a triangle with |ab|>|ac|, the median am, the angle bisector ad and the altitude ah divide the angle into 4 equal parts. find .

asked
User Armstrhb
by
8.4k points

1 Answer

4 votes

Final answer:

In a triangle with |AB| > |AC|, the median AM, the angle bisector AD, and the altitude AH divide the angle into 4 equal parts.

Step-by-step explanation:

In a triangle with |AB| > |AC|, the median AM, the angle bisector AD, and the altitude AH divide the angle into 4 equal parts.

Let's label the triangle as ABC, with AB > AC. We can use the properties of isosceles triangles and the Angle Bisector Theorem to find the measures of the angles.

  1. Since AB > AC, angle B is larger than angle C.
  2. Since the median AM divides side BC into two equal parts, angle BAM = MAC.
  3. Since the angle bisector AD divides angle BAC into two equal parts, angle BAD = DAC.
  4. Since the altitude AH is perpendicular to BC, angle BAH = CAH = 90 degrees.

Therefore, in triangle ABC, angles BAM, MAC, BAD, and DAC are all equal and divide the angle BAC into four equal parts.

Learn more about Triangle Properties

answered
User Dixit Panchal
by
7.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.