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on monday you jog at a constant 9.10 km/hr for 4.00 km, then you walk at a constant 3.50 km/hr for 0.250 hours, all in the same direction. what is the magnitude of your average velocity for the entire trip?

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User Jongware
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2 Answers

4 votes

Final answer:

The magnitude of the average velocity for the entire trip is approximately 7.07 km/hr, calculated by dividing the total distance of 4.875 km by the total time of 0.69 hours.

Step-by-step explanation:

To find the magnitude of your average velocity for the entire trip, we first need to calculate the total distance covered and the total time taken. Velocity is defined as the displacement per unit time, which in this case is straightforward because the student travels in a single direction without reversing.

The first part of the trip involves jogging at a constant speed of 9.10 km/hr for a distance of 4.00 km.

Time taken to jog = Distance/Speed = 4.00 km / 9.10 km/hr = 0.44 hours (approximately)

The second part involves walking at a constant speed of 3.50 km/hr for 0.250 hours.

Distance walked = Speed × Time = 3.50 km/hr × 0.250 hours = 0.875 km

Total distance traveled = 4.00 km + 0.875 km = 4.875 km

Total time taken = 0.44 hours + 0.250 hours = 0.69 hours (approximately)

Therefore, the average velocity is calculated by dividing the total distance by the total time.

Average Velocity = Total Distance / Total Time = 4.875 km / 0.69 hours ≈ 7.07 km/hr (approximately)

answered
User Denis Malinovsky
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8.2k points
6 votes

Final answer:

The magnitude of the average velocity for the entire trip is 5.43 km/hr.

Step-by-step explanation:

The magnitude of average velocity is calculated by dividing the total displacement by the total time taken. In this case, the jogger runs at a constant speed of 9.10 km/hr for a distance of 4.00 km, which takes 0.44 hours. Then, the jogger walks at a constant speed of 3.50 km/hr for 0.250 hours. To find the total displacement, we subtract the distance covered in the opposite direction from the distance covered in the forward direction. The total displacement is 3.75 km. Therefore, the total time is 0.44 + 0.250 = 0.69 hours. Finally, the magnitude of the average velocity is calculated as 3.75 km / 0.69 hr = 5.43 km/hr.

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User ZKK
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