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Obtain expressions in component form for the position vectors having the following polar coordinates. (a) 12,6 m, 160° counterclockwise from the +x axis?

asked
User Nullglob
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9.5k points

1 Answer

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To obtain the position vector in component form from polar coordinates, you can use trigonometric relationships. Given the polar coordinates (r, θ), where r is the radial distance and θ is the angle counterclockwise from the +x axis, you can use the following equations to find the position vector (x, y) in component form:

x = r * cos(θ)

y = r * sin(θ)

In your case, the polar coordinates are (r = 12 m, θ = 160° counterclockwise from the +x axis).

Let's calculate the position vector (x, y):

x = 12 m * cos(160°)

x = 12 m * (-0.866) (cos(160°) is approximately -0.866)

x ≈ -10.392 m

y = 12 m * sin(160°)

y = 12 m * 0.5 (sin(160°) is approximately 0.5)

y = 6 m

So, the position vector in component form is approximately (-10.392 m, 6 m).

answered
User Larrydalmeida
by
7.2k points
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