Question

The upper limit for the function f(x) = x^3 - 3x^2 - 2x + 15 is

3
5
4

Answer 1

Explanation:

I am assuming you need the local maximum of the function,

f(x) = x^3 - 3x^2 - 2x + 15

Find the derivative:

f'(x) = 3x^2 - 6x - 2

This = 0 for maxm/minm values of f(x),

x = -0.29, 2.29

The second derivative

f"(x) = 6x - 6 which is negative when x = -0.29 so this is the value of x at a maximum,

So the maximum is (-0.29)^3 - 3(-0.29)^2 - 2(-0.29 + 15

= 15.30 to the nearest hundredth.