Step-by-step explanation:
what is the problem ? it is all just to be read directly off the graph.
by the way, I don't see question 23 in the picture.
6. negatively accelerating (= slowing down, reducing speed, reducing forward speed, increasing backward speed, ...) : from 0 to 9 seconds.
7. positively accelerating (= speeding up, speed increases, reducing backwards speed, increasing forward speed, ...) : from 9 to 12 seconds, and from 17 to 20 seconds.
8. shape is drawn in the + zone : from 0 to 4 seconds, and from 18 to 25 seconds.
9. shape is drawn in the - zone (the object is moving with negative velocity = the object is moving backwards) : from 4 to 18 seconds.
10. the same as 8.
11. the same as 9.
12. the same as 8.
13. the same as 9.
14. the same as 8.
15. the same as 9.
16. in this case position change and distance change are the same. based on the given information of the graph we cannot distinguish between a position change compared to an original position and distance driven.
so, the slope pt/dt is always 1 (either positive/positive or negative/negative change along the line).
so, there is no negative slope.
17. see 16. but now
there is always a positive slope.
18. the same as 7.
but if it means "moving away from the x-axis" (speeding up in a forward motion or speeding up in a backwards motion - depends on the criteria your teacher set), then it is from 4 to 9 second, and from 18 to 20 seconds.
19. the same as 6.
but if it means "moving closer to the x-axis" (forward or backwards speeds are reduced), then it is from 0 to 4 seconds, from 9 to 12 seconds, and from 17 to 18 seconds.
20. constant velocity : from 12 to 17 seconds, and from 20 to 25 seconds.
21. constant acceleration (attention : this can be positive or negative !) : from 0 to 9 seconds, from 9 to 12 seconds, and from 17 to 20 seconds.
22. 0 velocity : just at 2 moments (!) : at 4 seconds, and at 18 seconds.
again, I cannot see question 23.