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3 votes
Can someone help me with this? I am stuck

(4x+11)/(2x+7) +(2x+10)/(2x+7)

Can someone help me with this? I am stuck (4x+11)/(2x+7) +(2x+10)/(2x+7)-example-1
asked
User Fbernier
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7.3k points

2 Answers

1 vote
Imma have to say answer a since when I solved it I got 3 so the only answer with a 3 is a
answered
User Andreas Jansson
by
8.1k points
6 votes

Answer:

(a) = 3, x ≠ -7/2

Explanation:

You want the sum (and restrictions) for ...


(4x+11)/(2x+7)+(2x+10)/(2x+7)

Sum

The two terms have a common denominator, so the sum will be the sum of the numerators, divided by that denominator.


(4x+11)/(2x+7)+(2x+10)/(2x+7) = (4x+11+2x+10)/(2x+7)=(6x+21)/(2x+7)\\\\\\=(3(2x+7))/(2x+7)=\boxed{3,\quad x\\e-(7)/(2)}

Restrictions

The domain of the expression must exclude values of x that make the expression undefined. The expression is undefined when its denominator is zero. So we require ...

2x +7 ≠ 0

2x ≠ -7

x ≠ -7/2 . . . . . the domain restriction

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answered
User Ocarlsen
by
8.4k points

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