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The equation of line k is y=


10x–8. Perpendicular to line k is line , which passes through the point (2,2). What is the equation of line ?

1 Answer

3 votes

Answer: y=-1/10x+2.2

Explanation:

The original equation is y=10x-8 and we need the perpendicular equation to it. First, find the "x" to the second equation. (Note: for perpendicular lines take the negative reciprocal of the original line)

y=10x-8 = 10x=-1/10x

y=-1/10x+b

Now, we have the point it needs to go through(2,2), so plug it (2,2) into the equation. x=2, y=2

2=-1/10(2)+b

solve for B

2=-2/10+b; 2/10=.2

2=.2 +b; add

2.2=b

y=-1/10x+2.2 or y=-1/10x+11/5

Extra: if equation was; y=-10x-8, the perpindicular is y=1/10x+1.8

The equation of line k is y= – 10x–8. Perpendicular to line k is line , which passes-example-1
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