Question

The area of a rectangle is 48 square feet, If the perimeter is 32 feet, find the length and width of the rectangle

Answer 1

Explanation:

x * y = 48

x + x + y + y = 32 These are 'given'

y = 48 / x from the firt equation.....sub into second equation

x + x + 48/x + 48/x = 32 simplify a bit to

2x + 96 / x - 32 = 0 multiply by 'x ' to get

2x^2 -32x + 96 = 0 now factor ...or use Quadratic Formula to find

x = 12 then y = 4

the rectangle length and width are 12 and 4 or 4 and 12 feet