Answer:
y= -2x+11
Explanation:
To find the equation of a line parallel to the given line y = -2x - 1 and passing through the point (4, 3), you can use the point-slope form of a linear equation, which is:
y - y₁ = m(x - x₁)
Where (x₁, y₁) is the point (4, 3), and m is the slope of the parallel line. Since the parallel line has the same slope as the given line (-2), you can substitute these values into the equation:
y - 3 = -2(x - 4)
Now, you can simplify and rearrange this equation to slope-intercept form (y = mx + b):
y - 3 = -2x + 8
Add 3 to both sides:
y = -2x + 11
So, the equation of the line parallel to y = -2x - 1 and passing through the point (4, 3) is y = -2x + 11.