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What is 1/10 of earth's pull

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User Mikkola
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To find 1/10 of the Earth's pull, we need to divide the total gravitational force by 10.
The force of gravity on Earth is approximately 9.8 meters per second squared (m/s^2).

Therefore, 1/10 of the Earth's pull is approximately 0.98 m/s^2 (9.8 m/s^2 divided by 10). This means that if we were to reduce the Earth's gravitational force by one-tenth, the resulting force would be around 0.98 m/s^2.
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User JiveTurkey
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