Let total surveyed people be
x
.
We are given that
10
%
i
.
e
.
10
x
100
people are
entertained by both TV and books.
Since
44
%
i
.
e
.
44
x
100
people are entertained by books.
∴
the number of people entertained ONLY by books is given by:-
(
number of people entertained by books
)
−
(
number of people entertained by BOTH books and TV
)
=
44
x
100
−
10
x
100
=
34
x
100
Similarly,
Since
46
%
i
.
e
.
46
x
100
people are entertained by books.
∴
the number of people entertained ONLY by TV is given by:-
(
number of people entertained by TV
)
−
(
number of people entertained by BOTH books and TV
)
=
46
x
100
−
10
x
100
=
36
x
100
∴
number of people entertained by EITHER books or TV:-
=
(
number of people entertained ONLY by books
)
+
(
number of people entertained ONLY by TV
)
+
(
People entertained by both TV and books
)
=
34
x
100
+
36
x
100
+
10
x
100
=
80
x
100
h
e
n
c
e
,
probability that a person will be entertained by either books or TV
=
(number of people entertained by EITHER books or TV)
/
(total number of people surveyed)
=
80
x
100
x
=
8
10
=
0.8