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6 (a) how many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once? (b) how many of these are odd numbers? (c) how many are greater than 330?

asked
User Royale
by
8.4k points

1 Answer

7 votes

Answer:

(a) 180

(b) 75

(c) 105

Explanation:

(a)

Restriction:

  • 0 cannot be the hundreds
  • each digit can be used only once

Hundreds possibility = 1, 2, 3, 4, 5, 6 → n = 6

Tens possibility = all 7 numbers except the hundreds → n = 7-1 = 6

Ones possibility = all 7 numbers except the hundreds & tens → n = 7-2 = 5

Total possibility = 6×6×5 = 180

(b)

Restriction:

  • 0 cannot be the hundreds
  • each digit can be used only once
  • Odd numbers (ends with 1, 3 or 5)

[i] Tens ≠ 0

Ones possibility = 1, 3, 5 → n = 3

Tens possibility = 1, 2, 3, 4, 5, 6 except the ones → n = 6-1 = 5

Hundreds possibility = 1, 2, 3, 4, 5, 6 except the ones & tens → n = 6-2 = 4

Possibility = 3×5×4 = 60

[ii] Tens = 0

Ones possibility = 1, 3, 5 → n = 3

Tens possibility = 0 → n = 1

Hundreds possibility = 1, 2, 3, 4, 5, 6 except the ones → n = 6-1 = 5

Possibility = 3×1×5 = 15

∴ Total possibility = [i] + [ii]

= 60 + 15

= 75

(c)

Restriction:

  • 0 cannot be the hundreds
  • each digit can be used only once
  • greater than 330 (not less than or equal to 330)

[i] numbers < 300

Hundreds = 1, 2 → n = 2

Tens = all 7 numbers except the hundreds → n = 7-1 = 6

Ones possibility = all 7 numbers except the hundreds & tens → n = 7-2 = 5

Possibility = 2×6×5 = 60

[ii] 300 ≤ numbers ≤ 330 AND Ones = 0, 1 or 2

Hundreds = 3 → n = 1

Tens = 0, 1, 2 → n = 3

Ones = 0, 1, 2 except the tens → n = 3-1 = 2

Possibility = 1×3×2 = 6

[iii] 300 ≤ numbers ≤ 330 AND Ones ≠ 0, 1 or 2

Hundreds = 3 → n = 1

Tens = 0, 1, 2 → n = 3

Ones = 4, 5, 6 → n = 3

Possibility = 1×3×3 = 9

∴ Total possibility = 180 - [i] - [ii] - [iii]

= 180 - 60 - 6 - 9

= 105

answered
User Kokosing
by
9.3k points

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