asked 220k views
4 votes
how many liters of a10% alcohol solutionmust be mixed with90liters of a60% solutionto get a30% solution?

1 Answer

5 votes

Answer:

135 litres

Explanation:

Key concept:

Remember that law,conservation of mass,which says

  • Mass before chemical change = mass after chemical change

Let the amount of alcohol to be mixed be x L.

According to the question,

10*x/100 + 90*60/100 = 30 * (90 + x) /100

Solve the particulated equation, and solve for x:

  • 10x/100 + 54 = 30(90+x)/100
  • (10x +5400)/100 = (2700 + 30x)/100 ( take LCM on LHS)
  • 10x + 5400 = 2700 +30x( 100 on the denominator get cancelled which is on both side)
  • 20x = 2700 (take 10x to RHS and 2700 to LHS)
  • x = 2700/20 = 270/2 = 135 (transpose 20 to RHS)
  • x = 135 L

Hence, 135 litres of alcohol solution with 90liters of a 60% solution to get a 30% solution.

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