Register

A compound contains 36.48% Na, 25.41% S and 38.11% O. What is this compound's empirical formula?

A compound contains 36.48% Na, 25.41% S and 38.11% O. What is this compound's empirical formula?
asked 95.7k views
1 vote
A compound contains 36.48% Na, 25.41% S and 38.11% O. What is this compound's empirical formula?

asked
User Smartdirt
by
7.5k points

1 Answer

6 votes

Answer: Na2SO3

Explanation: Solved as the following steps in the picture below

A compound contains 36.48% Na, 25.41% S and 38.11% O. What is this compound's empirical-example-1
answered
User Rhushikesh
by
9.0k points
← Prev Question Next Question →

Related questions

User Eugene Gordin
asked Nov 25, 2015 186k views
What's the empirical formula of 36.48% Na 25.41% S 38.11% O
Eugene Gordin asked Nov 25, 2015
by Eugene Gordin
7.0k points
2 answers
5 votes
186k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Link Copied!