Question

Select the correct answer.

A student has samples of five different types of metal. She measures the mass and volume of each sample. The measurements she took are in the
table.

Answer 1

The question pertains to choosing the correct tools for measuring volume and mass in the context of Chemistry. Appropriate tools include graduated cylinders, balances or scales, and measuring tapes or rulers, depending on the object and its physical properties.

Step-by-step explanation:

The student's question involves selecting appropriate tools for specific measurement tasks and understanding the units and instruments related to mass and volume measurements, which are common tasks in Chemistry. Choosing the correct measurement tool depends on the object being measured and its properties.

Choose the Appropriate Tool for Measurements

• The volume of a water balloon might be best measured using a graduated cylinder by the water displacement method.
• The length of a basketball court can be measured using a long measuring tape or a meter ruler.
• The weight of an apple is most accurately determined using a balance or scale.
• To determine the volume of a milk carton, one could use the method of length x width x height if it's a regular shape or a graduated cylinder for irregular shapes through water displacement.

Measurement of Mass and Volume in Chemistry

When weighing an iron sample from a mixture, a magnetic separation could be used followed by weighing the separated iron using an analytical balance. Measurements of mass are generally taken using an analytical balance, while the volume of liquids can be measured with a graduated cylinder or a pipet, and the volume of solids can be calculated if they have a geometric shape or by water displacement if they are irregular.

Answer 2

By calculating the density of the unknown metal sample and comparing it with the known metal samples, it is inferred that the unknown sample is likely to be lead (Option C: lead 11.34).

To identify the unknown metal sample, we can calculate its density and compare it with the densities of the known metal samples. The density is given by the formula: density = mass / volume.

For the unknown sample:

Density = 33.5 g / 3.2 cm^3 ≈ 10.47 g/cm^3.

Now, we compare this density with the densities of the known metal samples:

Aluminum: 14.6 g / 5.4 cm^3 ≈ 2.70 g/cm^3.

Iron: 33.1 g / 4.2 cm^3 ≈ 7.87 g/cm^3.

Lead: 35.2 g / 3.1 cm^3 ≈ 11.34 g/cm^3.

Magnesium: 10.6 g / 6.1 cm^3 ≈ 1.74 g/cm^3.

Silver: 47.2 g / 4.5 cm^3 ≈ 10.49 g/cm^3.

Comparing the calculated density of the unknown sample (10.47 g/cm³) with the densities of the known samples, it is closest to the density of lead (11.34 g/cm³). Therefore, the unknown sample is likely to be lead.