Question

If the volume of the reaction vessel in part b is 0.500 L, what amount of Br2 (in moles) is formed during the first 15.0 s of the reaction

Answer 1

The amount of Br2 formed in the first 15 seconds of the reaction, given the volume of the reaction vessel and the instantaneous rate at 15 seconds, is calculated to be 0.1725 moles.

Step-by-step explanation:

The instantaneous rate of the reaction at 15 s is given as 0.023 mol L-¹ s¯¹. This rate is in terms of volume (L), but the question specifies a volume of the reaction vessel, so we need to take this into account.

The amount of Br2 formed can be calculated by multiplying this rate by the volume and the time. With a volume of 0.500 L and a time of 15.0 s, using the formula Amount (in moles) = Rate x Volume x Time, we get:

• Amount (in moles) = 0.023 mol L-¹ s¯¹ x 15 s x 0.500 L = 0.1725 moles

Therefore, 0.1725 moles of Br2 is formed in the first 15 seconds of the reaction.

Learn more about Chemical Reaction Rates