a = ∠2 = 90° and b = 90°.
In a set of parallel lines cut by a transversal, remote interior angles are supplementary. So, we can use this property to find the values of
.
Given:
1. ∠1 and ∠3 are remote interior angles of ∠5:
∠1 + ∠3 = 180°
2. ∠1 and ∠2 are remote interior angles of ∠a:
∠1 + ∠2 = 180°
3. ∠2 and ∠3 are remote interior angles of ∠b:
∠2 + ∠3 = 180°
Now, let's solve for
:
From equation (1):
∠1 + ∠3 = 180°
From equation (2):
∠1 + ∠2 = 180°
Subtracting equation (2) from equation (1) to eliminate ∠1:
(∠1 + ∠3) - (∠1 + ∠2) = 180° - 180°
∠3 - ∠2 = 0
∠3 = ∠2
So, a = ∠2.
Now, let's consider equation (3):
∠2 + ∠3 = 180°
Since we know ∠3 = ∠2, we can substitute:
∠2 + ∠2 = 180°
2∠2 = 180°
∠2 = 90°
So, b = 90°.
Complete the question:
∠1 and ∠3 are remote interior angles of ∠5 .∠1 and ∠2 are remote interior angles of ∠a. ∠2 and ∠3 are remote interior angles of ∠b. find values of a and b.