Question

What is the probability that a random firing of CC267 would result in fewer than 5 bullets hitting the target CC267 weapon fires 7 bullets automatically at a target 1,910 meters away. The number of bullets that will hit the target is random, with a pdf shown below:

Answer 1

Explanation:

1. Identify the relevant values:

- Number of trials (n): CC267 fires 7 bullets.

- Probability of success (p): The probability that a bullet hits the target.

- Number of successes (k): We want to find the probability of fewer than 5 bullets hitting the target, so k can be 0, 1, 2, 3, or 4.

2. Calculate the probability of success (p):

Since the number of bullets hitting the target is random, we need more information to determine the probability of success. If you can provide the probability of a bullet hitting the target, I can help you with the calculation.

3. Plug the values into the binomial probability formula:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

where X follows a binomial distribution with parameters n and p.