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What is the limit of the function? f(x)=4x11−3x8+2x−11 Select True or False for each statement. Limit statement True False limx→−∞f(x)=∞ True – limit as x rightwards arrow negative infinity of f left parenthesis x right parenthesis equals infinity False – limit as x rightwards arrow negative infinity of f left parenthesis x right parenthesis equals infinity limx→∞f(x)=−∞ True – limit as x rightwards arrow infinity of f left parenthesis x right parenthesis equals negative infinity False – limit as x rightwards arrow infinity of f left parenthesis x right parenthesis equals negative infinity

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User Pitazzo
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1 Answer

3 votes

Answer:


\displaystyle \lim_(x\to\infty)f(x) = \infty, \ \text{DNE}


\displaystyle\lim_(x\to-\infty)f(x)= -\infty, \ \ \text{DNE}

Explanation:

We can find the limit as x approaches infinity for the function:


\displaystyle f(x)=4x^(11)-3x^8+2x-11

by examining what happens to each term:


\displaystyle \lim_(x\to\infty)\!\left(4x^(11)-3x^8+2x-11\right)


  • \displaystyle 4x^{11 goes to infinity because
    a(\infty)^n = \infty, \ \ a > 0, \ \ n > 0

  • \displaystyle -3x^8 goes to negative infinity

  • 2x goes to infinity

  • 11 is irrelevant

So, we can evaluate the limit as:


\displaystyle \lim_(x\to\infty)f(x) = \infty - \infty + \infty

↓ canceling the infinities ...
a - a = 0


\boxed{\displaystyle \lim_(x\to\infty)f(x) = \infty, \ \text{DNE}}

We have to add "DNE" ("Does Not Exist") to the end of our answer because infinity is not a number; therefore it will never be reached.

_____

We can also use the same method to solve for the limit of the function as x approaches negative infinity:


\displaystyle \lim_(x\to-\infty)\!\left(4x^(11)-3x^8+2x-11\right)


= -\infty - \infty -\infty


\boxed{\lim_(x\to-\infty)f(x)= -\infty, \ \ \text{DNE}}

Notice that for the term
\displaystyle -3x^8, the
x-factor is positive because it is raised to an even power:


(-a)^n > 0, \ \ n \in \text{R}, \ \ n \!\!\mod 2=0

answered
User Pash
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