Question

What is an equation of the line that passes through the point (−3,−1) and is perpendicular to the line 3x−2y=18?

Answer 1

3x - 2y = 18

-2y = -3x + 18

y = (3/2)x - 9

Since the original line has slope 3/2, a perpendicular line will have slope -2/3.

y + 1 = (-2/3)(x + 3)

y + 1 = (-2/3)x - 2

y = (-2/3)x - 3

3y = -2x - 9

2x + 3y = -9