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A fair 6-sided die is rolled four times. What is the probability that the sequence of rolls is 4,3,2,1 ? Write your answer as a fraction or a decimal, rounded to four decimal places.

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To find the probability, we need to consider the number of favorable outcomes (getting the sequence 4, 3, 2, 1) and the total number of possible outcomes when rolling a fair 6-sided die four times. Since each roll is independent, the probability for each roll is 1/6.

The probability of rolling a 4 on the first roll is 1/6, for rolling a 3 on the second roll is 1/6, for rolling a 2 on the third roll is 1/6, and for rolling a 1 on the fourth roll is 1/6.

To find the probability of all four rolls occurring in a specific sequence, we multiply the probabilities together:

(1/6) * (1/6) * (1/6) * (1/6) = 1/1296.

Therefore, the probability of getting the sequence 4, 3, 2, 1 when rolling a fair 6-sided die four times is 1/1296, which is approximately 0.0008 when rounded to four decimal places.
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User Rockford Lhotka
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