Question

If the 1st value of a table is -3 and the 8th value is -384, what are the values inbetween?

Answer 1

-3, -6, -12, -24, -48, -96, -192, -384

Explanation:

an = a₁r∧n-1

-384 = -3r⁸⁻¹

-384 = -3r⁷

`(-384)/(-3)` =
`(-3r^(7) )/(-3)`

128 = r⁷

`\sqrt[7]{128}` =
`\sqrt[7]{r^(7) }`

2 = r

-3 (2) = -6

-6(2) = -12

-12(2) = -24

-24(2) = -48

-48(2) = -96

-96(2) = -192

-192(2) = -384